Two hellbores hitting a ship with two "weakest" sh
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VulcanDropout
- Lieutenant JG
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Two hellbores hitting a ship with two "weakest" sh
If a ship is hit by two hellbores and has two (or more) 'weakest' shields, can the owner choose that the main portion of the damage be allocated to two different shields?
For example, if an undamaged D7 were hit by 2 OL HB at range 8 (damage 10+9 each) could it choose that the first HB spreads its damage 2/2/10/2/1/2 and the second damage spread is 2/2/1/2/10/2?
I am assuming that the allocation decision preceeds the actual allocation of damage, so the damage from the first HB doesn't bring the 3rd shield down to a dozen boxes and break the tie for weakest shield.
While I'm on the subject, I'm assuming that phaser fire in the same impulse won't break a 2 (or more) way tie before the HB damage is allocated.
For example, if an undamaged D7 were hit by 2 OL HB at range 8 (damage 10+9 each) could it choose that the first HB spreads its damage 2/2/10/2/1/2 and the second damage spread is 2/2/1/2/10/2?
I am assuming that the allocation decision preceeds the actual allocation of damage, so the damage from the first HB doesn't bring the 3rd shield down to a dozen boxes and break the tie for weakest shield.
While I'm on the subject, I'm assuming that phaser fire in the same impulse won't break a 2 (or more) way tie before the HB damage is allocated.
Re: Two hellbores hitting a ship with two "weakest"
If both hellbores are fired from the same ship, then their damage will be combined. (4K3f)Zaron wrote:If a ship is hit by two hellbores and has two (or more) 'weakest' shields, can the owner choose that the main portion of the damage be allocated to two different shields?
For example, if an undamaged D7 were hit by 2 OL HB at range 8 (damage 10+9 each) could it choose that the first HB spreads its damage 2/2/10/2/1/2 and the second damage spread is 2/2/1/2/10/2?
I am assuming that the allocation decision preceeds the actual allocation of damage, so the damage from the first HB doesn't bring the 3rd shield down to a dozen boxes and break the tie for weakest shield.
While I'm on the subject, I'm assuming that phaser fire in the same impulse won't break a 2 (or more) way tie before the HB damage is allocated.
This will produce a rather unfortunate 20+18. Assuming an undamaged D7, the damage will be 1 burnthrough, then 19 on any shield other than #1. Then 4 on 3 other shields and 3 on the remaining two.
Re: Two hellbores hitting a ship with two "weakest"
He can choose which of the 2equal weakest shields takes the main part.Zaron wrote:If a ship is hit by two hellbores and has two (or more) 'weakest' shields, can the owner choose that the main portion of the damage be allocated to two different shields?
As noted above, it depends on whether it is 2 hellbores from 1 ship or 2 ships. i.e. are they in the same volley. 2 ships is 2 volleys, so each resolves the weakest shields at the point you resolve that volley. He would be able to choose the first volley to go on which shield he wants, but unless something else has happened in between (or it was batteried away), the second hellbore will now hit that shield again as it will be the weakest shield after the first lot of damage.
That also depends on whether the phasers were from a different ship or not. Phasers fired in the same impulse from a different ship can weaken a shield for the subsequent hellbore volley, but phasers from the same ship as the hellbores won't.While I'm on the subject, I'm assuming that phaser fire in the same impulse won't break a 2 (or more) way tie before the HB damage is allocated.
Regarding the phaser question:
If the phasers are declared as "directed targeting" at the same target as the hellbores (from the same ship etc) then there will be a volley of hellbores and a volley containing the phasers.
If the phasers are declared as "directed targeting" at the same target as the hellbores (from the same ship etc) then there will be a volley of hellbores and a volley containing the phasers.
"Captain" Terry O'Carroll, fourteen papers published including six best of issue
"Man, Terry, you are like a loophole seeking missle!" - Mike West

"Man, Terry, you are like a loophole seeking missle!" - Mike West

It still can't weaken the shield for the hellbore 'weakest shield' choice though, unless as noted above they were from different ships.terryoc wrote:Regarding the phaser question:
If the phasers are declared as "directed targeting" at the same target as the hellbores (from the same ship etc) then there will be a volley of hellbores and a volley containing the phasers.
Storeylf, yes it does, I have a published command note on the subject.
It works like this:
Declare hellbores and phasers, with directed targeting.
ETA: This can't be resolved as one volley because hellbores cannot use directed targeting. These are split into two volleys.
Resolve phasers first. This will ding the shield.
Then resolve the hellbores. At this point, you determine which shield is weakest.
It works like this:
Declare hellbores and phasers, with directed targeting.
ETA: This can't be resolved as one volley because hellbores cannot use directed targeting. These are split into two volleys.
Resolve phasers first. This will ding the shield.
Then resolve the hellbores. At this point, you determine which shield is weakest.
"Captain" Terry O'Carroll, fourteen papers published including six best of issue
"Man, Terry, you are like a loophole seeking missle!" - Mike West

"Man, Terry, you are like a loophole seeking missle!" - Mike West

I beg to differ, but your command note (which I haven't seen) isn't in line with this clarification by MWest. Have I missed a further ruling on this? What you are suggesting was my first thought when the split volley rule was introduced, but it was clarified to not allow that.terryoc wrote:Storeylf, yes it does, I have a published command note on the subject.
It works like this:
Declare hellbores and phasers, with directed targeting.
ETA: This can't be resolved as one volley because hellbores cannot use directed targeting. These are split into two volleys.
Resolve phasers first. This will ding the shield.
Then resolve the hellbores. At this point, you determine which shield is weakest.
No. The weakest shield determination is made before applying any damage from the volleys from a single ship.Steve Robinson wrote:
In example #2, since the damage to the #1 shield was from 2 volleys, could the firing player decide to have the volley from the phaser resolved first in an attempt to reduce the #1 shield to the "weakest"?
This was why I was careful in my wording in my first post above, using the terms fire from a ship where phasers were concerned.The issue is that having the phasers and hellbores be divided into separate volleys is an artificial mechanism introduced to not penalize the ability to use directed damage just because hellbores are fired normally. Adding in this exception does not mean that it should be used to give even more advantage to this situation.
Therefore, regardless of whether the phasers are fired in directed mode or not, the weakest shield is determined prior to that "double-volley" exception. Doing otherwise will instead advantage hellbores even more than they already are. (And believe me, hellbores do not need any more advantages.)
PS I'm rather partial to Hydrans, so making sure I'm using the correct ruling on this is significant to me.
Yes, according to that ruling directed fire can never ding a shield.storeylf wrote:I beg to differ, but your command note (which I haven't seen) isn't in line with this clarification by MWest. Have I missed a further ruling on this? What you are suggesting was my first thought when the split volley rule was introduced, but it was clarified to not allow that.
mjwest wrote:No. The weakest shield determination is made before applying any damage from the volleys from a single ship.Steve Robinson wrote:In example #2, since the damage to the #1 shield was from 2 volleys, could the firing player decide to have the volley from the phaser resolved first in an attempt to reduce the #1 shield to the "weakest"?